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楼层直达
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只看该作者 15楼 发表于: 2003-12-10
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最初由 sigmond 发布
这个应该是高中学生就可以做的吧
偶也来一个,偶只知道答案,不会做

从-无穷到+无穷的 exp(-t*t/2)dt的积分
答案是 (2*PI)^(1/2)
求过程

r u sure? as i write, anything smaller than 3 is not the answer.
in this question, 3 and 1% will affect the answer greatly. without count them in, u will just get zero marks

BTW, just my wild guess, the real thing matter's here is e. the natural log base.
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只看该作者 16楼 发表于: 2003-12-10
是不是要列一个方程式,然后求极限值啊,这只是一个思路哦

歡 迎 來 到 俺 の 筗 夏 夜 之 夢
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只看该作者 17楼 发表于: 2003-12-11
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最初由 sigmond 发布
自乘一次轉 polar??什么意思

这是个偶函数 我知道啊,就是2*从0到+无穷的 exp(-t*t/2)dt的积分
过程是什么? exp(-t*t/2)dt的原函数是什么?


sorry..... can't type Chinese........

solution = sqrt(Int (exp(-x^2 / 2) * exp(-y^2 / 2) dxdy))

in polar system, x^2 + y^2 = r^2

=> Solution = sqrt(Int (exp(-r^2 / 2) rdrd theta))

☆ 偶是新人請多多指教! ☆
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只看该作者 18楼 发表于: 2003-12-11
d theta 是 dθ 对吧
我明白了。 Int (exp(-r^2 / 2) rdr 从0到+无穷 = 1
Int (d theta) 从0到2π = 2π
然后就是答案了

楼上的真强啊~~~

请问你是大学几年纪啊。因为我还没有学到把积分自乘 然后转换到解析几何,这个思路实在巧妙。

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只看该作者 19楼 发表于: 2003-12-11
求极限值是必然的 因为无穷是不能用来定积分的,只能先积分再求极限

谢谢你帮助啦

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只看该作者 20楼 发表于: 2003-12-11
我觉得答案是应该和存钱的总天数有关系的,所以此题没有一个固定的答案。
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只看该作者 21楼 发表于: 2003-12-11
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最初由 seiyafan 发布
我觉得答案是应该和存钱的总天数有关系的,所以此题没有一个固定的答案。

with a long enough time, the winner will emerge clearly with ur question though. it's surely not a fixed number for different precondition, that's why i think ppl give out a number without even consider the precondition funny.
regardless to whatever precondition, i think e, the most efficient number in the universe, is the essential part of the answer as this whole thing is n/N >=logf(n)/logf(N). visually, it's a log curve always below a straight line.(the differential may not be)
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只看该作者 22楼 发表于: 2004-01-08
看了半天!!答案:应该是无解。
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只看该作者 23楼 发表于: 2004-01-08
holy...optimization problem..
i can't solve it!! itz too hard..


"Never apologize for saying what you feel. It's like apologizing for being real."
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只看该作者 24楼 发表于: 2004-01-16
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最初由 aaabbbccc 发布

with a long enough time, the winner will emerge clearly with ur question though. it's surely not a fixed number for different precondition, that's why i think ppl give out a number without even consider the precondition funny.
regardless to whatever precondition, i think e, the most efficient number in the universe, is the essential part of the answer as this whole thing is n/N >=logf(n)/logf(N). visually, it's a log curve always below a straight line.(the differential may not be)


I don't understand where the n/N >= log f(n) / log f(N) comes from. Also why is e the most efficient number? efficient in what sense? I haven't studied maths for a while, so forgive me if I'm asking silly questions.
All I managed to get is 100000*(1+(m-3))^(n/m) = amout at maturity. Where can I go from there

バカにするな !
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只看该作者 25楼 发表于: 2004-01-17
我想应该是14天一次啊。
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只看该作者 26楼 发表于: 2004-01-17
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最初由 ambivalence 发布


I don't understand where the n/N >= log f(n) / log f(N) comes from. Also why is e the most efficient number? efficient in what sense? I haven't studied maths for a while, so forgive me if I'm asking silly questions.
All I managed to get is 100000*(1+(m-3))^(n/m) = amout at maturity. Where can I go from there


faint, this problem seems keep come to the surface and refuses to die.

if u take n*N days, u will get that equation. if N is the answer then f(n)^N<=f(N)^n , f(x) is the equation for 1 round with x days. and the initial value doesnt really matter here unless the bank has some charge per day.


btw, this whole thing is a variation of n/N >=log(n)/log(N) and the answer for that is N=e. (1/N is the derivative of log(n)/log(N) when n==N, it can be seen more clearly on a graph)


e is the most efficient number is refering to if a number system is base e, u will need minimun symbols(states) to store a number in general (it's actrually the same problem as the one above). in computer, it means base 3 is most efficient for storing data, base 2 is not that bad also. anything else will waste a lot of states in general.
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只看该作者 27楼 发表于: 2004-01-18
ok, I won't pretend I've understood what you said, because I haven't. I'll just take your word for it ;-)

バカにするな !
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只看该作者 28楼 发表于: 2004-01-18
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最初由 ThunderBird 发布
做不来


真的有答案吗?好象无解的说。

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“不懂的话,多看,很不懂的话,再问!要不问多了,人家也烦的!”
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只看该作者 29楼 发表于: 2004-01-19
好像不是很难,,,,but我做不出来。
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