Not so sure about it. I believe you do the cross sectional area for this problem. Probably my advice is all wrong.
First, there is work to pump all the water to the top of the cylinder. This is the hard part. We use cross sectional area. I don't remember how since the cylinder is on the side. Once you get the cross sectional area. You do an integral from 0 to some number for the function of the cross sectional area times 1000 times g and y. You integrate the function and then you get the work.
Work = mgh. From the density, we get mass is 1000 kg.
Second, once the water is pump to the top. We have to pump it 1 meters high more. This is the easy part.
You just multiply - 1000 kg times g times 1 meter and that's the work
Last, you add the work up. the work to lift is 1 meters and the work to pump water to the top.
Hoope this helps...